fix(server): rename awk variable 'in' to 'inside' in wg-peerctl remove
'in' became a reserved keyword in GNU awk 5.x causing syntax errors when removing peers. Peer deletion silently failed as a result. Co-Authored-By: Claude Sonnet 4.6 <noreply@anthropic.com>
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@@ -408,13 +408,13 @@ cmd_remove() {
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local tmp
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local tmp
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tmp="$(mktemp)"
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tmp="$(mktemp)"
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awk -v pk="$client_pubkey" '
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awk -v pk="$client_pubkey" '
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BEGIN {in=0; block=""; keep=1}
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BEGIN {inside=0; block=""; keep=1}
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/^\[Peer\]/ {
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/^\[Peer\]/ {
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if (in && keep) printf "%s", block
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if (inside && keep) printf "%s", block
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in=1; block=$0 ORS; keep=1; next
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inside=1; block=$0 ORS; keep=1; next
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}
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}
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{
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{
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if (in) {
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if (inside) {
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block = block $0 ORS
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block = block $0 ORS
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if ($0 ~ /^PublicKey[[:space:]]*=/) {
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if ($0 ~ /^PublicKey[[:space:]]*=/) {
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line=$0
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line=$0
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@@ -426,7 +426,7 @@ cmd_remove() {
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print
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print
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}
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}
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END {
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END {
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if (in && keep) printf "%s", block
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if (inside && keep) printf "%s", block
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}
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}
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' "$WG_CONF" > "$tmp"
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' "$WG_CONF" > "$tmp"
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mv "$tmp" "$WG_CONF"
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mv "$tmp" "$WG_CONF"
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